Completed the about_scoring_project koan

[stevendes]

Completed and ready for review!

[AlejoAsd]

Lots of comments! I went deep into some Python-specific concepts. Please address my code comments to see if my explanations made sense to you.

[AlejoAsd]

Dice have 6 possible values, but the repeated_nums variable in your solution has 10 total values. Was this done because you were getting list index out of range errors when the array had only 6 values, and increasing the size fixed it? If that is the case, then let me explain why.

Sequences (list, tuple, set, string, etc.) in Python and most programming languages are zero-based. This means that the elements are numbered starting at 0. The first element has index 0, the second element has index 1, and so on. When you create repeated_nums with 6 elements, you get the following:

# Index           0  1  2  3  4  5
# Die Value       1  2  3  4  5  6 
# repeated_nums  [0, 0, 0, 0, 0, 0]

The out of index errors were happening because you were iterating over the values of the dice,

for number in dice:

which set number to some value between 1 and 6, but were using this value as an index.

    repeated_nums[number] [...]

The problem here is that values go from 1 to 6, but indexes go from 0 to 5. This means that whenever the value of number is 6, you will get an list index out of range error, because the list does not have an index 6; its maximum index is 5.

A quick solution to this is to substract 1 from the value of the dice, so that both the indexes and dice values are in the same range.

repeated_nums = [0, 0, 0, 0, 0, 0]
for number in dice:
    repeated_nums[number-1] = repeated_nums[number] + 1

[stevendes]

I didn't even notice this error because for some reason I forgot that the dice goes only to 6 (I did not forget that it can't be 0 tho haha)

So what I was trying to do is to compare the values to the numbers from 1 to 9, when trying to make the list shorter I run with that error, so that fixes it!

[stevendes]

All comments addressed!