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There is a simpler algorithm for xor basis. basis = []
def reduce(x):
for b in basis:
x = min(x, x ^ b)
return x
def insert(x):
x = reduce(x)
if x:
basis.append(x)
return True
return False |
Author
|
Updated the code. Please have a look |
Owner
|
bit length shouldn't be a parameter |
Author
Actually it's needed to print xor basis upto certain number of bits. It is anyway optional. |
Collaborator
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Xor basis is an useful technique to solve many complex problems in Competitive Programming involving bitwise xors. This pull request adds code for xor basis.