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CheezItMan
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Nov 29, 2020
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Nice work Kal, thanks for getting this in. The methods you wrote all work, but I had some feedback on time/space complexity.
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| # Time complexity: O(n) | ||
| # Space complexity: O(n) | ||
| def factorial(n) |
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| # Time complexity: O(n^2), where n is the length of the string | ||
| # Space complexity: O(n^2), where n is the length of the string | ||
| def reverse(s, pointer = s.length - 1) |
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| # Time complexity: O(n), where n is the length of the string. (More precisely, n/2) | ||
| # Space complexity: O(n), where n is the length of the string. (More precisely, n/2) | ||
| def reverse_inplace(s) |
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| # Time complexity: O(n) | ||
| # Space complexity: O(n) | ||
| def bunny(n) |
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| # Time complexity: O(n), where n is the length of the string | ||
| # Space complexity: O(n), where n is the length of the string | ||
| def nested(s, parens_counter = 0, pointer = 0) |
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| # Time complexity: O(n), where n is the length of the string | ||
| # Space complexity: O(n), where n is the length of the string | ||
| def search(array, value, pointer = 0) |
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| # Time complexity: O(n), where n is the length of the string (More precisely, n/2) | ||
| # Space complexity: O(n), where n is the length of the string (More precisely, n/2) | ||
| def is_palindrome(s, length = s.length, pointer = 0) |
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